Tìm x: $\frac{x+3}{97}$ + $\frac{x+8}{92}$ = $\frac{x+15}{85}$ + $\frac{x+27}{73}$ gấp ạ huhu cảm ơn mn nhiềuu

`ttcolor{purple}{@thuyhien}`

`(x + 3)/97  + (x + 8)/92  = (x + 15)/85  + (x + 27)/73`

`(x + 3)/97 + 1 + (x + 8)/92 + 1 = (x + 15)/85 + 1 + (x + 27)/73 + 1`

`(x + 100)/97  + (x + 100)/92  = (x + 100)/85  + (x + 100)/73`

`=> (x + 100)/97  + (x + 100)/92 - (x + 100)/85 - (x + 100)/73 = 0`

`(x + 100) . (1/97 + 1/92 - 1/85 - 1/73) = 0`

`text(Mà)` `1/97 + 1/92 - 1/85 - 1/73 ne 0`

`=> x + 100 = 0`

`x = 0 - 100`

`x = -100`

`text(Vậy)` `x = -100`