Viết công thức cấu tạo đầy đủ và thu gọn của phân tử sau:

C4H9Br ( 4 cái)

Đáp án:

Công thức cấu tạo $\rm C_4H_9Br$:

$\rm \hspace{0,95cm}H \hspace{0,55cm}H \hspace{0,6cm}H \hspace{0,55cm}H \\ \hspace{1,05cm}| \hspace{0,8cm}| \hspace{0,8cm}| \hspace{0,8cm}|\\ H-C-C-C-C-Br\\ \hspace{1,05cm}| \hspace{0,8cm}| \hspace{0,8cm}| \hspace{0,8cm}|\\ \hspace{0,95cm}H \hspace{0,55cm}H \hspace{0,6cm}H \hspace{0,55cm}H $

Thu gọn: $\rm CH_3-CH_2-CH_2-CH_2Br$

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$\rm \hspace{0,95cm}H \hspace{0,55cm}H \hspace{0,6cm}H \hspace{0,55cm}H \\ \hspace{1,05cm}| \hspace{0,8cm}| \hspace{0,8cm}| \hspace{0,8cm}|\\ H-C-C-C-C-H\\ \hspace{1,05cm}| \hspace{0,8cm}| \hspace{0,8cm}| \hspace{0,8cm}|\\ \hspace{0,95cm}H \hspace{0,55cm}H \hspace{0,6cm}Br \hspace{0,4cm}H $

Thu gọn: $\rm CH_3-CH_2-CHBr-CH_3$

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$\rm \hspace{0,9cm}H \hspace{0,6cm}H \hspace{0,6cm}H \\ \hspace{1,05cm}| \hspace{0,8cm}| \hspace{0,8cm}| \\ H-C-C-C-Br\\ \hspace{1,05cm}| \hspace{0,8cm}| \hspace{0,8cm}| \\ \hspace{0,95cm}H \hspace{0,4cm}CH_3 \hspace{0,2cm}H $

Thu gọn: $\rm CH_3-CH(CH_3)-CH_2Br$

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$\rm \hspace{0,9cm}H \hspace{0,6cm}Br \hspace{0,4cm}H \\ \hspace{1,05cm}| \hspace{0,8cm}| \hspace{0,8cm}| \\ H-C-C-C-H\\ \hspace{1,05cm}| \hspace{0,8cm}| \hspace{0,8cm}| \\ \hspace{0,95cm}H \hspace{0,4cm}CH_3 \hspace{0,2cm}H $

Thu gọn: $\rm CH_3-C(Br)(CH_3)-CH_3$