sos mình câu 5 6 với

Đáp án + Giải thích các bước giải:

Câu 5:

$\rm CH_3-CH-CH_2-CH_3 +Cl_2\\\hspace{1,6cm} | \\ \hspace{1,6cm}CH_3$

$\rm \xrightarrow[1:1]{as} \left[\begin{matrix} \rm CH_3-CH_2-CH-CH_2Cl\\ \hspace{0,7cm}|\\ \rm \hspace{1,3cm}CH_3\\ \rm CH_3-CH_2-CCl-CH_3\\ \hspace{1cm}|\\ \rm \hspace{1,5cm}CH_3\\ \rm CH_3-CHCl-CH-CH_3\\ \hspace{1,4cm}|\\ \rm \hspace{2cm}CH_3\\ \rm CH_2Cl-CH_2-CH-CH_3\\ \hspace{1,6cm}|\\ \rm \hspace{2,1cm}CH_3\\ \end{matrix}\right. +HCl$

Câu 6:

$\rm n_{C_3H_8}=\dfrac{4,48}{22,4}=0,2(mol)$

Bảo toàn nguyên tố C:

$\rm n_{CO_2}=3n_{C_3H_8}=0,6(mol)$

$\rm V_{CO_2}=0,6×22,4=13,44(l)$

Bảo toàn nguyên tố H:

$\rm n_{H_2O}=4n_{C_3H_8}=0,8(mol)$

$\rm m_{H_2O}=0,8×18=14,4(g)$