Giải PHƯƠNG TRÌNH x+7/3 + x+5/4 = x+3/5 + x+1/6

 `(x+7)/3+(x+5)/4=(x+3)/5+(x+1)/6`

`( (x+7)/3+2)+((x+5)/4+2)=((x+3)/5+2)+((x+1)/6+2)`

`( (x+7)/3+6/3)+((x+5)/4+8/4)=( (x+3)/5+10/5)+((x+1)/6+12/6)`

`(x+7+6)/3+(x+5+8)/4=(x+3+10)/5+(x+1+12)/6`

`(x+13)/3+(x+13)/4=(x+13)/5+(x+13)/6`

`(x+13)/3+(x+13)/4-(x+13)/5-(x+13)/6=0`

`(x+13)(1/3+1/4-1/5-1/6)=0`

`x+13=0 (`vì `1/3+1/4-1/5-1/6\ne 0)`

`x=-13`

Vậy `x=-13`