rút gọn ạ, mong đc mn giúpppppppppppppppppppppppppppp

Đáp án+Giải thích các bước giải:

`M=({asqrt{a}+1}/{a-sqrt{a}-2}+{sqrt{a}}/{2-sqrt{a}}):{1-sqrt{a}}/{2-sqrt{a}}`

Điều kiện : `a>0;a\ne1;a\ne4`

`=[{(sqrt{a}+1)(a-sqrt{a}+1)}/{(sqrt{a}-2)(sqrt{a}+1)}-{sqrt{a}}/{sqrt{a}-2}]:{1-sqrt{a}}/{2-sqrt{a}}` 

`=[{(sqrt{a}+1)(a-sqrt{a}+1)-sqrt{a}(sqrt{a}+1)}/{(sqrt{a}-2)(sqrt{a}+1)}].{2-sqrt{a}}/{1-sqrt{a}}` 

`=[{(sqrt{a}+1)(a-sqrt{a}+1-sqrt{a})}/{(sqrt{a}-2)(sqrt{a}+1)}].{2-sqrt{a}}/{1-sqrt{a}}` 

`=[{(sqrt{a}+1)(a-2sqrt{a}+1)}/{(sqrt{a}-2)(sqrt{a}+1)}].{2-sqrt{a}}/{1-sqrt{a}}` 

`=[{(sqrt{a}+1)(sqrt{a}-1)^2}/{(sqrt{a}-2)(sqrt{a}+1)}].{2-sqrt{a}}/{1-sqrt{a}}` 

`={(sqrt{a}-1)^2}/{sqrt{a}-2}.{sqrt{a}-2}/{sqrt{a}-1}` 

`=sqrt{a}-1`

Vậy với `a>0;a\ne1;a\ne4` thì `M=sqrt{a}-1`