(x+2)/327 + (x+3)/326 + (x+4)/325 + (x+5)/324 + (x+349)/5 = 0 x = ? Help

Đáp án + Giải thích các bước giải:

`(x+2)/327 + (x+3)/326 + (x+4)/325 + (x+5)/324 + (x+349)/5 = 0`

`=>((x+2)/327+1)+((x+3)/326+1)+((x+4)/325+1)+((x+5)/324+1)+((x+349)/5-4)=0`

`=>(x+2+327)/327+(x+3+326)/326+(x+4+325)/325+(x+5+324)/324+(x+349-20)/5=0`

`=>(x+329)/327+(x+329)/326+(x+329)/325+(x+329)/324+(x+329)/5=0`

`=>(x+329).(1/327+1/326+1/325+1/324+1/5)=0`

Mà: `1/327+1/326+1/325+1/324+1/5\ne0` 

`=>x+329=0`

`=>x=-329`

Vậy `x=-329`