(X-3)(2x+1)=0 (5x-10)(8- 2x)=0 (9-3x)(15+3x)=0

Đáp án:

Giải thích các bước giải:

  (X-3)(2x+1)=0

→\(\left[ \begin{array}{l}x-3=0\\2x+1=0\end{array} \right.\) 

→\(\left[ \begin{array}{l}x=3\\x=-1/2\end{array} \right.\) 

  (5x-10)(8- 2x)=0

→\(\left[ \begin{array}{l}5x-10=0\\8- 2x=0\end{array} \right.\) 

→\(\left[ \begin{array}{l}x=2\\x=4\end{array} \right.\) 

  (9-3x)(15+3x)=0

→\(\left[ \begin{array}{l}9-3x=0\\15+3x=0\end{array} \right.\) 

→\(\left[ \begin{array}{l}x=3\\x=-5\end{array} \right.\)