2.(x-3)^2-x.(2x-5)=7

`2(x-3)^2 - x(2x-5)=7`

`=> 2(x^2-6x+9) - (2x^2-5x)=7`

`=> 2x^2-12x+18-2x^2+5x=7`

`=>-7x+18=7`

`=> -7x=7-18`

`=>-7x=-11`

`=> x=-11:(-7)`

`=> x=11/7`

Vậy `x=11/7`

`@Ryan`