giúp mình câu này đc ko?mình ko làm đc câu này 12 chia hết cho (x + 3)

`12\vdotsx+3`

`=>x+3in Ư(12)={+-1;+-2;+-3;+-4;+-6;+-12}`

Ta có bảng sau:

$\begin{array}{|c|c|c|}\hline \text{}x+3&\text{}1&\text{}-1&\text{}2&\text{}-2&\text{}3&\text{}-3&\text{}4&\text{}-4&\text{}6&\text{}-6&\text{}12&\text{}-12\\\hline \text{}x&\text{}-2&\text{}-4&\text{}-1&\text{}-5&\text{}0&\text{}-6&\text{}1&\text{}-7&\text{}3&\text{}-9&\text{}9&\text{}-15\\\hline\end{array}$

Vậy `x in{-2;-4;+-1;-5;0;-6;-7;3;+-9;-15}`