căn(x-2)+1/3=1

Đáp án:

 `\sqrt{x-2}+\frac{1}{3}=1` `(đk: x\ge2)`

`=> \sqrt{x-2}=1-\frac{1}{3}`

`=> \sqrt{x-2}=\frac{3}{3}-\frac{1}{3}`

`=> \sqrt{x-2}=\frac{2}{3}`

Bình phương 2 vế ta có:

`=> (\sqrt{x-2})^{2}=(\frac{2}{3})^{2}`

`=> x-2=\frac{4}{9}`

`=> x=\frac{4}{9}+\frac{9}{9}`

`=> x=\frac{13}{9}` `(ktmđk)`

Vậy `x\in{\emptyset}`

________________________

`\frac{\sqrt{x-2}+1}{3}=1` `(x\ge2)`

`=> \frac{\sqrt{x-2}+1}{3}=\frac{3}{3}`

`=> \sqrt{x-2}+1=3`

`=> \sqrt{x-2}=2`

Bình phương 2 vế:

`=> (\sqrt{x-2})^{2}=2^{2}`

`=> x-2=4`

`=> x=6(tmđk)`

Vậy `x=6`