giúp tớ giải bài1 voiii

Em tham khảo nha:

\(\begin{array}{l}
a)\\
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
CuC{l_2} + 2NaOH \to Cu{(OH)_2} + 2NaCl\\
b)\\
{n_{HCl}} = \dfrac{{200 \times 3,65\% }}{{36,5}} = 0,2\,mol\\
{n_{CuO}} = {n_{CuC{l_2}}} = \dfrac{{0,2}}{2} = 0,1\,mol\\
{m_{CuO}} = 0,1 \times 80 = 8g\\
{n_{Cu{{(OH)}_2}}} = {n_{CuC{l_2}}} = 0,1\,mol\\
{m_{Cu{{(OH)}_2}}} = 0,1 \times 98 = 9,8g
\end{array}\)