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Đáp án:$\dfrac{{ - 16}}{3}$

Giải thích các bước giải:

$\begin{array}{l}
\dfrac{{{4^7}.{{\left( { - 18} \right)}^3}}}{{{6^7}.{{\left( { - 8} \right)}^2}}}\\
 = \dfrac{{{{\left( {{2^2}} \right)}^7}.{{\left( { - {3^2}.2} \right)}^3}}}{{{{\left( {2.3} \right)}^7}.{{\left( {{2^3}} \right)}^2}}}\\
 = \dfrac{{ - {2^{14}}{{.3}^6}{{.2}^3}}}{{{2^7}{{.3}^7}{{.2}^6}}}\\
 = \dfrac{{ - {2^{17}}{{.3}^6}}}{{{2^{13}}{{.3}^7}}}\\
 = \dfrac{{ - {2^4}}}{3}\\
 = \dfrac{{ - 16}}{3}
\end{array}$