(4x-3) mũ 4= (4x-3) mũ 2. giải thích kĩ vs ạ

`( 4x - 3 )^4 = ( 4x - 3 )^2`

`⇒ ( 4x - 3 )^4 - ( 4x - 3 )^2 = 0`

`⇒ ( 4x - 3 )^2 . ( 4x - 3 )^2 - ( 4x - 3 )^2 . 1 = 0`

`⇒ ( 4x - 3 )^2 . [ ( 4x - 3 )^2 - 1 ] = 0`

`TH1:`

`( 4x - 3 )^2 = 0`

`⇒ 4x - 3 = 0`

`⇒ 4x = 3`

`⇒ x = 3/4`

`TH2:`

`( 4x - 3 )^2 - 1 = 0`

`⇒ ( 4x - 3 )^2 = 1`

   `@ 4x - 3 = 1`

    `⇒ 4x = 4`

    `⇒ x = 1`

  `@ 4x - 3 = -1`

    `⇒ 4x = 2`

    `⇒ x = 1/2`

Vậy `x ∈ { 3/4 ; 1 ; 1/2 }`