Help với mn ...........

Đáp án:

 `A=\frac{\sqrt{x}-1}{\sqrt{x}}+\frac{1-\sqrt{x}}{x+\sqrt{x}}` `(x>0)`

`=\frac{\sqrt{x}-1}{\sqrt{x}}+\frac{1-\sqrt{x}}{\sqrt{x}.(\sqrt{x}+1)}`

`=\frac{(\sqrt{x}-1).(\sqrt{x}+1)}{\sqrt{x}.(\sqrt{x}+1)}+\frac{1-\sqrt{x}}{\sqrt{x}.(\sqrt{x}+1)}`

`=\frac{x-1+1-\sqrt{x}}{\sqrt{x}.(\sqrt{x}+1)}`

`=\frac{x-\sqrt{x}}{\sqrt{x}.(\sqrt{x}+1)}`

`=\frac{\sqrt{x}.(\sqrt{x}-1)}{\sqrt{x}.(\sqrt{x}+1)}`

`=\frac{\sqrt{x}-1}{\sqrt{x}+1}`

Vậy `bbA` `=\frac{\sqrt{x}-1}{\sqrt{x}+1}`