giải giúp mình vs nhaa

`#aithao`

`(19/17-100/49+129/131)/(3/17-3/49-3/131)`

`=(1+2/17-2-2/49+1-2/131)/(3/17-3/49-3/131)`

`=(2/17-2/49-2/131)/(3/17-3/49-3/131)`

`=[2(1/17-1/49-1/131)]/[3(1/17-1/49-1/131)`

`=2/3`

`=>2/3`

$\text{~Học tốt~}$