a,11^2x-7=11^11 b, 2^2x+1=2^7 c,3^x+3^x+2=9^17+27^12 d,5^x+1-5^x=100.25^29 giúp e bốn ý vs ạ=( cần rất gấp

Đáp án:

$\begin{array}{l}
a){11^{2x - 7}} = {11^{11}}\\
 \Leftrightarrow 2x - 7 = 11\\
 \Leftrightarrow 2x = 18\\
 \Leftrightarrow x = 9\\
Vậy\,x = 9\\
b){2^{2x + 1}} = {2^7}\\
 \Leftrightarrow 2x + 1 = 7\\
 \Leftrightarrow 2x = 6\\
 \Leftrightarrow x = 3\\
Vậy\,x = 3\\
c){3^x} + {3^{x + 2}} = {9^{17}} + {27^{12}}\\
 \Leftrightarrow {3^x} + {9.3^x} = {\left( {{3^2}} \right)^{17}} + {\left( {{3^3}} \right)^{12}}\\
 \Leftrightarrow {3^x}.\left( {1 + 9} \right) = {3^{34}} + {3^{36}}\\
 \Leftrightarrow {3^x}.10 = {3^{34}}.\left( {1 + {3^2}} \right)\\
 \Leftrightarrow {3^x}.10 = {3^{34}}.10\\
 \Leftrightarrow {3^x} = {3^{34}}\\
 \Leftrightarrow x = 34\\
Vậy\,x = 34\\
d){5^{x + 1}} - {5^x} = {100.25^{29}}\\
 \Leftrightarrow {5^x}.5 - {5^x} = {4.5^2}.{\left( {{5^2}} \right)^{29}}\\
 \Leftrightarrow {5^x}.4 = {4.5^2}{.5^{58}}\\
 \Leftrightarrow {5^x} = {5^{60}}\\
 \Leftrightarrow x = 60\\
Vậy\,x = 60
\end{array}$