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Đáp án:

`3x(x-2)-x+2=0`

`=>3x(x-2)-(x-2)=0`

`=>(3x-1)(x-2)=0`

`=>` \(\left[ \begin{array}{l}3x-1=0\\x-2=0\end{array} \right.\) `=>` \(\left[ \begin{array}{l}3x=1\\x=2\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=2\end{array} \right.\) 

Vậy `x\in{2;1/3}`

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`16x^2-9(x+1)^2=0`

`=>(4x)^2-[3(x+1)]^2=0`

`=>(4x)^2-[3x+3]^2=0`

`=>(4x-3x-3)(4x+3x+3)=0`

`=>(x-3)(7x+3)=0`

`=>` \(\left[ \begin{array}{l}x-3=0\\7x+3=0\end{array} \right.\) `=>` \(\left[ \begin{array}{l}3\\x=-\dfrac{3}{7}\end{array} \right.\)

Vậy `x\in{-3/7;3}`