5 sao+hay nhấttttttttttttttttttttttttttttttttt

Đáp án:

`P=6/(sqrtx+2)` nguyên

`<=>sqrt(x+2)∈ Ư(6) ={2;3;6}`

`=>x+2=4;9;36`

`=>x=2;7;34`

`2) P=(3sqrtx+7)/(sqrtx+1)`

`P=3+4/(sqrtx+1)` nguyên

`<=>sqrtx+1∈ Ư(4)=1;2;4`

`=>sqrtx=0;1;3`

`=>x=0;1;9`

`3)P =(5sqrtx)/(2sqrtx+1)`

`TH1: x=0` tm

`TH2`:với x `khác 0

`=>P=5/(2+1/(sqrtx))`nguyên

`<=> 1/(sqrtx)+2∈ Ư(5) =5`

`=>1/(sqrtx)=3`

`=>sqrtx=1/3`

`=>x=1/9(ktm)`

Vậy`x=0`

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