giúp e với ạ e đag cần gấp

#Wan 

`k) (2x-1)/x = 4/3 (x \ne 0)`

`=> 3.(2x-1) = 4x`

`=> 6x - 3 = 4x`

`=> 6x - 4x =3`

`=> 2x = 3`

`=> x = 3/2 (t//m)` 

 Vậy `x = 3/2` 

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`i) 4/(x-2) = 7/(3x+1) (ĐK : x \ne 2 ; x \ne -1/3)` 

`=> 7(x+2) = 4(3x+1)`

`=> 7x + 14 = 12x + 4`

`=> 7x - 12x = -14 + 4`

`=> -5x = -10`

`=> x = 2 (t//m)` 

Vậy `x = 2` 

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`k) 5/(8x-2) = -4/(7-x)(ĐK : x\ne 7 ; x \ne 2\8)`

`=> 5.(7-x) = -4(8x-2)`

`=> 35-5x = -32x + 8`

`=> 32x- 5x = -35 + 8`

`=> 27x = -27`

`=> x = -1 (t//m)` 

Vậy `x = -1`