x^2=x^3 3^x-1 = 27 3^x+1 = 9 6^x-1 = 36 3^2x+1+ = 27 x^50 = x

Đáp án+Giải thích các bước giải:

`x^2=x^3`

`=>x^2-x^3=0`

`=>x^2(1-x )=0`

`=>[(x^2=0),(1-x=0):}`

`=>[(x=0),(x=1-0):}`

`=>[(x=0),(x=1):}`

Vậy `x in{0;1}

______________________________________________

`3^{x-1} = 27 `

`=>3^{x-1} = 3^3 `

`=>x-1=3 `

`=>x=3+1 `

`=>x=4 `

Vậy `x=4`

______________________________________________

`3^{x+1} = 9`

`=>3^{x+1} =3^2`

`=>x+1=2`

`=>x=2-1`

`=>x=1`

Vậy `x=1`

______________________________________________

`6^{x-1} = 36 `

`=>6^{x-1} = 6^2`

`=>x-1=2`

`=>x=2+1`

`=>x=3`

Vậy `x=3`

______________________________________________

`3^{2x+1}= 27 `

`=>3^{2x+1}=3^3 `

`=>2x+1=3 `

`=>2x=3-1 `

`=>2x=2 `

`=>x=2:2 `

`=>x=1 `

Vậy `x=1`

______________________________________________

`x^50 = x `

`=>x^50 - x =0`

`=>x(x^49 - 1) =0`

`=>[(x=0),(x^49-1=0):}`

`=>[(x=0),(x^49=0+1):}`

`=>[(x=0),(x^49=1):}`

`=>[(x=0),(x=1):}`

Vậy `x in{0;1}`