...........................help..............................

`@` Lời giải:

`1/(1*2) + 1/(2*3) + ... + 1/(x(x+1)) = 2022/2023`

`=> 1 - 1/2 + 1/2 - 1/3 + ... + 1/x - 1/(x+1) = 2022/2023`

`=> 1 - 1/(x+1) = 2022/2023`

`=> 1/(x+1) = 1-2022/2023`

`=> 1/(x+1) = 1/2023`

`=> x+1=2023`

`=> x = 2023-1`

`=> x = 2022`

Vậy `x = 2022`