1/3(x-3)+1/2(x+2)=0,25

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$\frac{1}{3}$$(x-3)$ + $\frac{1}{2}$$(x+2)$=$0,25$

($\frac{1}{3}$$x$ - $1$) + ( $\frac{1}{2}$$x$+$1$)= $0,25$

$\frac{1}{3}$$x$ - $1$ + $\frac{1}{2}$$x$+$1$ = $0,25$

($\frac{1}{3}$$x$ + $\frac{1}{2}$$x$) + ($-1$ $+$ $1$) = $0,25$

$\frac{5}{6}$$x$ = $0,25$

$\frac{5}{6}$$x$ = $\frac{1}{4}$

$x$ = $\frac{1}{4}$ : $\frac{5}{6}$

$x$ = $\frac{3}{10}$

Vậy $x$ = $\frac{3}{10}$

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