Giúp vs ạ mk đg cần

c, $\bigg(\dfrac{6-2\sqrt 2}{3-\sqrt 2}-\dfrac{5}{\sqrt 5}\bigg):\dfrac{1}{2-\sqrt 5}\\=\bigg(\dfrac{2(3-\sqrt 2)}{3-\sqrt 2}-\sqrt 5\bigg).(2-\sqrt 5)\\=(2-\sqrt 5)^2\\=9-4\sqrt 5$

d, $\sqrt{(2-\sqrt 5)^2}-\sqrt 5\\=|2-\sqrt 5|-\sqrt 5\\=\sqrt 5-2-\sqrt 5\\=-2$