tìm x 1/4 . 2/6 . 3/8 . 4/10 . 5/12 ... 30/62 . 31/64 = 2^x

`#Aka#`

`1/4 . 2/6 . 3/8 . 4/10 . 5/12 ... 30/62 . 31/64 = 2^x`

`1/2.2 . 2/2.3 . 3/2.4 . 4/2.5 . 5/2.6 ... 30/2.31 . 31/2.32 = 2^x`

`(1.2.3.4.5...30.31)/(2.2.2.3.2.4.2.5.2.6...2.31.2.32) 2^x`

`1/(2^31 . 32)=2^x`

`1/(2^31 .2^5)=2^x`

`1/2^36=2^x`

`2^-36=2^x`

`x=-36`

Vậy `x=-36`