6^3x+1=36^x+3 Giúp mik vss

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`6^(3x + 1) = 36^(x + 3)`

`<=> 6^(3x + 1) = (6^2)^(x + 3)`

`<=> 6^(3x + 1) = 6^(2x + 6)`

`<=> 6^(3x + 1) - 6^(2x + 6) = 0`

`<=> 6^(3x + 1). [1 - 6^(5 - x)]= 0`

`<=>` \(\left[ \begin{array}{l}6^{3x + 1} = 0\\1 - 6^{5 - x} = 0\end{array} \right.\)

`<=>` \(\left[ \begin{array}{l}x ∈ ∅ \\6^{5 - x} = 1\end{array} \right.\)

`<=> 5 - x = 0`

`<=> x = 5`

Vậy `x = 5`

$@Ri$