so sánh: `199^20` và `2003^15`

Bạn tham khảo nhé :

`Ta có `: $199^{20}$`<`$200^{20}$`=`$(8.25)^{20}$`=`$(2^3.5^2)^{20}$`=`$2^{60}$.$5^{40}$

$2003^{15}$`>`$2000^{15}$`=`$(16.125)^{15}$`=`$(2^4.5^3)^{15}$`=`$2^{60}$.$5^{45}$ 

`Ta thấy` : $2^{60}$.$5^{40}$<$2^{60}$.$5^{45}$

`⇒`$200^{20}$`<`$2000^{15}$

`Mà` $199^{20}$`<`$200^{20}$ `và` $2003^{15}$`>`$2000^{15}$

`⇒`$199^{20}$`<`$2003^{15}$

`Vậy` $199^{20}$`<`$2003^{15}$

---Chúcbạnhọctốt---

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