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Đáp án:

Bài `4` :

a, `x=68`

b, `x=23`

c, `x=4`

d, `x=14`

Bài `5` :

a, `x=68`

b, `x=4`

c, `x=2^8047 -5`

d, `x=19`

Giải thích các bước giải:

a,

`5(x+35)=515`

`=>x+35=515/5`

`=>x+35=103`

`=>x=103-35`

`=>x=68`

Vậy `x=68`

b,

`12x-33=3^2 .3^3`

`=>12x-33=9.27`

`=>12x-33=243`

`=>12x=243+33`

`=>12x=276`

`=>x=276/12`

`=>x=23`

Vậy `x=23`

c,

`6.x-5=19`

`=>6.x=19+5`

`=>6.x=24`

`=>x=24:6`

`=>x=4`

Vậy `x=4`

d,

`4.(x-12)+9=17`

`=>4.(x-12)=17-9`

`=>4.(x-12)=8`

`=>x-12=8:4`

`=>x-12=2`

`=>x=2+12`

`=>x=14`

Vậy `x=14`

Bài `5` :

a,

`515:(x+35)=5`

`=>x+35=515/5`

`=>x+35=103`

`=>x=103-35`

`=>x=68`

Vậy `x=68`

b,

`20-2(x+4)=4`

`=>2(x+4)=20-4`

`=>2(x+4)=16`

`=>x+4=16/2`

`=>x+4=8`

`=>x=8-4`

`=>x=4`

Vậy `x=4`

c,

`(10+2x):4^2011 =4^2013`

`=>10+2x=4^2013+ 4^2011`

`=>10+2x=4^4024`

`=>2x=4^4024 -10`

`=>x=(4^4024 -10):2`

`=>x=[(2^2 )^4024 -10]:2`

`=>x=(2^8048 -10):2`

`=>x=2^8047 -5`

Vậy `x=2^8047 -5`

d,

`12(x-1):3=4^3 +2^3`

`=>12(x-1):3=64+8`

`=>12(x-1):3=72`

`=>12(x-1)=72 . 3`

`=>12(x-1)=216`

`=>x-1=216:12`

`=>x-1=18`

`=>x=18+1`

`=>x=19`

Vậy `x=19`