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\(n_{Zn}^{} = \frac{{13}}{{65}} = 0,2\;{\text{mol}}\)

\(a)Zn + 2HCl \to ZnCl_2^{} + H_2^{}\)

\(b)Zn + 2HCl \to ZnCl_2^{} + H_2^{}\)

\(\;\,{\text{  0}}{\text{,2                             0}}{\text{,2}}\)

\(V_{H_2^{}}^{} = 0,2.22,4 = 4,48l\)

\(c)CuO + H_2^{}\xrightarrow{{t_{}^o}}Cu + H_2^{}O\)

\({\text{    0}}{\text{,2      0}}{\text{,2          0}}{\text{,2}}\)

\({\text{m}}_{Cu}^{} = 0,2.64 = 12,8g\)