1. a,2^x3+4=58 b,(5-x)^5=32 c,(5x-6)^3=64 d,(3x)^3=(2x+1)^3

`a )2^(x3) + 4 = 58`

`=> 2^(3x) = 58 - 4`

`=> 2^(3x) = 54`

Vì `2^5 < 54 < 2^6` nên `3x = O/ ( x in NN)`

`=> x = O/`

Vậy `x = O/`

`b ) (5-x)^5 = 32`

`=> (5-x)^5 = 2^5`

`=> 5-x = 2`

`=> x = 5-2`

`=> x = 3`

Vậy `x = 3`

`c ) (5x-6)^3 = 64`

`=> (5x-6)^3 = 4^3`

`=> 5x - 6 =4`

`=> 5x = 4+6`

`=> 5x = 10`

`=> x = 10:5`

`=> x = 2`

Vậy `x = 2`

`d ) (3x)^3 = (2x+1)^3`

`=> 3x = 2x+1`

`=> 3x - 2x = 1`

`=> (3-2)x = 1`

`=> 1x = 1`

`=>x =1`

Vậy `x = 1`

`#dtkc`