`(64/27)^x =( 4 . 5^9. 7^10 - 5^11 . 7^9 )/ (35^9 . 4)`

Đáp án:

Giải thích các bước giải:

`(64/27)^x = {4*5^9 * 7^10 - 5^11 * 7^9}/{35^9 * 4}`$\\$
`=> (64/27)^x = {4*5^9 * 7^10 - 5^11 * 7^9}/{(7*5)^9 * 4}`$\\$
`=> (64/27)^x = {4*5^9 * 7^10 - 5^11 * 7^9}/{7^9 * 5^9* 4}`$\\$
`=> (64/27)^x = {7^9 * 5^9(7*4-5^2)}/{7^9 * 5^9* 4}`$\\$
`=> (64/27)^x = {7*4 - 25}/4`$\\$
`=> (64/27)^x = {28 - 25}/4`$\\$
`=> (64/27)^x = 3/4`$\\$
`=> 64^x/27^x = 3/4`
`=> 64^x * 4 = 27^x * 3`$\\$
`=> (4^3)^x * 4 = (3^3)^x * 3`$\\$
`=> 4^{3x} * 4 = 3^{3x} * 3`$\\$
`=> 4^{3x + 1} = 3^{3x + 1}`$\\$
`=> 4^{3x + 1} - 3^{3x + 1} = 0`$\\$
Nếu `3x + 1 \geq 1`$\\$
`=> 4^{3x + 1} - 3^{3x + 1} \ne 0`$\\$
`=> 3x + 1 = 0`$\\$
`=> 3x = -1`$\\$
`=> x = -1/3`