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Đáp án:
$1) 4x+\dfrac{1}{3}=\dfrac{3}{2}$
$⇒ 4x = \dfrac{3}{2}-\dfrac{1}{3}$
$⇒ 4x= \dfrac{9}{6}-\dfrac{2}{6}$
$⇒ 4x= \dfrac{7}{6}$
$⇒ x= \dfrac{7}{6}:4$
$⇒ x= \dfrac{7}{6}.\dfrac{1}{4}$
$⇒ x= \dfrac{7}{24}$
Vậy x= $\dfrac{7}{24}$
~~~~~~~~~~~~~~~~~
$2) \dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}$
$⇒ (\dfrac{5}{15}-\dfrac{6}{15})+3x= \dfrac{3}{4}$
$⇒ \dfrac{-1}{15}+3x= \dfrac{3}{4}$
$⇒ 3x= \dfrac{3}{4}-(-\dfrac{1}{15})$
$⇒ 3x= \dfrac{45}{60}-(-\dfrac{4}{60})$
$⇒ 3x= \dfrac{49}{60}$
$⇒ x= \dfrac{49}{60}:3$
$⇒ x= \dfrac{49}{180}$
Vậy x= $\dfrac{49}{180}$
~~~~~~~~~~~~~~~~~~
$3) 2.(\dfrac{3}{4}-5x)= \dfrac{4}{5}-3x$
$⇒ (2.\dfrac{3}{4})-(2.5x)= \dfrac{4}{5}-3x$
$⇒ \dfrac{3}{2}-10x= \dfrac{4}{5}-3x$
$⇒ -10x+3x= \dfrac{4}{5}-\dfrac{3}{2}$
$⇒ -7x= \dfrac{8}{10}-\dfrac{15}{10}$
$⇒ -7x= \dfrac{-7}{10}$
$⇒ x= \dfrac{-7}{10}.\dfrac{1}{-7}$
$⇒ x= \dfrac{-7}{-70}$
$⇒ x= \dfrac{1}{10}$
Vậy x= $\dfrac{1}{10}$
~~~~~~~~~~~~~~~~~~~
$4) \dfrac{3}{2}-4.(\dfrac{1}{4}-x)= \dfrac{2}{3}-7x$
$⇒ \dfrac{3}{2}-(4.\dfrac{1}{4})+(4.x)= \dfrac{2}{3}-7x$
$⇒ \dfrac{3}{2}-1+4x =\dfrac{2}{3}-7x$
$⇒ (\dfrac{3}{2}-\dfrac{2}{2})+4x= \dfrac{2}{3}-7x$
$⇒ \dfrac{1}{2}+4x= \dfrac{2}{3}-7x$
$⇒ 4x+7x= \dfrac{2}{3}-\dfrac{1}{2}$
$⇒ 11x= \dfrac{4}{6}-\dfrac{3}{6}$
$⇒ 11x= \dfrac{1}{6}$
$⇒ x= \dfrac{1}{6}.\dfrac{1}{11}$
$⇒ x= \dfrac{1}{66}$
Vậy x= $\dfrac{1}{66}$
~~~~~~~~~~~~~~~~~~
$5) 3.(\dfrac{1}{2}-x)+\dfrac{1}{3}=\dfrac{7}{6}-x$
$⇒ (3.\dfrac{1}{2})-(3.x)+\dfrac{1}{3}=\dfrac{7}{6}-x$
$⇒ \dfrac{3}{2}-3x+\dfrac{1}{3}= \dfrac{7}{6}-x$
$⇒ (\dfrac{3}{2}+\dfrac{1}{3})-3x= \dfrac{7}{6}-x$
$⇒ (\dfrac{9}{6}+\dfrac{2}{6})-3x= \dfrac{7}{6}-x$
$⇒ \dfrac{11}{6}-3x= \dfrac{7}{6}-x$
$⇒ -3x+x= \dfrac{7}{6}-\dfrac{11}{6}$
$⇒ -2x= \dfrac{-4}{6}$
$⇒ -2x= -\dfrac{2}{3}$
$⇒ x= (-\dfrac{2}{3}).(-\dfrac{1}{2})$
$⇒ x= \dfrac{2}{6}$
$⇒x= \dfrac{1}{3}$
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