Bài 2: Tình a) 27*3: 3*2 b) (3/5) *15 : (9/25) *5 c) 5- (-5/11) *0 + (1/3)*2: 3

Đáp án + Giải thích các bước giải:

`a)`

`27^3 : 3^2`

`= ( 3^3 )^3 : 3^2 `

`= 3^( 3.3 ) : 3^2  `

`= 3^9 : 3^2 `

`= 3^( 9 - 2 ) `

`= 3^7 `

`b)`

`( 3/5 )^(15) : ( 9/25 )^5 `

`= ( 3/5 )^(15) : [ ( 3/5 )^2 ]^5`

`= ( 3/5 )^(15) : ( 3/5 )^(10)`

`= ( 3/5 )^( 15 - 10 )`

`= ( 3/5 )^5 `

`c)`

`5 - ( -5/11 )^0 + ( 1/3 )^2 : 3 `

`= 5 - 1 + 1/3^2. 1/3`

`= 4 + 1/( 3^2. 3 ) `

`= 4 + 1/3^3`

`= 4 + 1/27`

`= 108/27 + 1/27`

`= ( 108 + 1 )/27`

`= 109/27`