Làm ơn giúp mình với

$B=\frac{x\sqrt2}{2\sqrt{x}+x\sqrt2}+\frac{\sqrt{2x}-2}{x-2}=\frac{x\sqrt2}{\sqrt{2x}(\sqrt2+\sqrt{x})}+\frac{\sqrt{2}(\sqrt{x}-\sqrt2)}{(\sqrt{x}-\sqrt2)(\sqrt{x}+\sqrt2)}=\frac{\sqrt{x}}{\sqrt2+\sqrt{x}}+\frac{\sqrt{2}}{\sqrt{x}+\sqrt2}=1$