Tìm `x` biết: `{x+5}/{2015} + {x+6}/{2014} + {x+7}/{2013} + {x+8}/{2012} + {x+9}/{2011}=-5` giúp mình với ạ

`(x+5)/2015 + (x+6)/2014 + (x+7)/2013 + (x+8)/2012 + (x+9)/2011 = -5`

`=> (x+5)/2015 + (x+6)/2014 + (x+7)/2013 + (x+8)/2012 + (x+9)/2011 + 5 = -5+5`

`=> ((x+5)/2015 +1)+ ((x+6)/2014 +1)+ ((x+7)/2013 +1)+( (x+8)/2012+1) + ((x+9)/2011+1) =0`

`=> (x+2020)/2015 + (x+2020)/2014 + (x+2020)/2013 + (x+2020)/2012 + (x+2020)/2011 = 0`

`=> (x+2020) . (1/2015 + 1/2014 + 1/2013 + 1/2012 + 1/2011) = 0`

Vì `1/2015 + 1/2014 + 1/2013 + 1/2012 + 1/2011 > 0` nên :

`=> x + 2020 = 0`

`=> x = 0 - 2020`

`=> x = -2020`

Vậy `x = -2020`

`#dtkc`