$\frac{x+1}{2}$= $\frac{x+2}{3}$

`(x+1)/2=(x+2)/3`

`=>(3(x+1))/6=(2(x+2))/6`

`=>3(x+1)=2(x+2)`

`=>3x+3=2x+4`

`=>3x-2x=4-3`

`=>x=1`

Vậy, `x=1.`