Gíup em câu c và d với ạ

Đáp án:

 $c) (\dfrac{7}{10}-\dfrac{5}{2}).\dfrac{2}{3}-2$

$= (\dfrac{7}{10}-\dfrac{25}{10}).\dfrac{2}{3}-2$

$= (-\dfrac{9}{5}).\dfrac{2}{3}-2$

$= \dfrac{-6}{5}-2$

$= \dfrac{-6}{5}-\dfrac{10}{5}$

$= -\dfrac{16}{5}$

$d) (1+\dfrac{7}{3}):(2-\dfrac{5}{12}-\dfrac{3}{2})$

$= (\dfrac{3}{3}+\dfrac{7}{3}):(\dfrac{24}{12}-\dfrac{5}{12}-\dfrac{18}{12})$

$= \dfrac{10}{3}:\dfrac{1}{12}$

$= \dfrac{10}{3}.12$

$=40$