x-1/59+x-2/58+x-3/57=x-4/56+x-5/55+x-6/54 Giúp e vs

Đáp án:

`( x - 1 ) / 59 + ( x - 2 ) / 58 + ( x - 3 ) / 57 = ( x - 4 ) / 56 + ( x - 5 ) / 55 + ( x - 6 ) / 54`

`<=> ( x - 1 ) / 59 + ( x - 2 ) / 58 + ( x - 3 ) / 57 - 3 = ( x - 4 ) / 56 + ( x - 5 ) / 55 + ( x - 6 ) / 54 - 3`

`<=> ( x - 1 ) / 59 - 1 + ( x - 2 ) / 58 - 1 + ( x - 3 ) / 57 - 1 = ( x - 4 ) / 56 - 1 + ( x - 5 ) / 55 - 1 + ( x - 6 ) / 54 - 1`

`<=> ( x - 60 ) / 59 + ( x - 60 ) / 58 + ( x - 60 ) / 57 = ( x - 60 ) / 56 + ( x - 60 ) / 55 + ( x - 60 ) / 54`

`<=> ( x - 60 ) / 59 + ( x - 60 ) / 58 + ( x - 60 ) / 57 - ( x - 60 ) / 56 - ( x - 60 ) / 55 - ( x - 60 ) / 54 = 0`

`<=> ( x - 60 ) ( 1/59 + 1/58 + 1/57 - 1/56 - 1/55 - 1/54 ) = 0`

Mà  `1/59 + 1/58 + 1/57 - 1/56 - 1/55 - 1/54 \ne 0`

`=> x - 60 = 0`

`<=> x = 60`

Vậy  `x =60.`