`M=((2/5-2/9+2/11)/(7/5-7/9+7/11)-(1/3-1/4+1/5)/(1 1/6-7/8+7/10)):2021/2022`

Đáp án:

`M=((2/5-2/9+2/11)/(7/5-7/9+7/11)-(1/3-1/4+1/5)/(1 1/6-7/8+7/10)):2021/2022`

`=((2/5-2/9+2/11)/(7/5-7/9+7/11)-(1/3-1/4+1/5)/(7/6-7/8+7/10)). 2022/2021`

`=((2.(1)/5-2.(1)/9+2.(1)/11}/{7 . 1/5-7 . 1/9+7. 1/11}-{1/3-1/4+1/5}/{{7}/{2}.{1}/{3}-{7}/{2}.{1}/{4}+{7}/{2}.{1}/{5}}). 2022/2021`

`=({2(1/5-1/9+1/11)}/{7(1/5-1/9+1/11)}-{1/3-1/4+1/5}/{{7}/{2}(1/3-1/4+1/5)}). 2022/2021`

`=(2/7-1:7/2). 2022/2021`

`=(2/7-1. 2/7). 2022/2021`

`=(2/7-2/7). 2022/2021`

`=0. 2022/2021`

`=0`

Vậy `M=0`

`#Kiro`

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