trả lời nhanh giúp mình nhé

Em tham khảo nha:

\(\begin{array}{l}
c)\\
ZnS + 2HCl \to ZnC{l_2} + {H_2}S\\
2{H_2}S + S{O_2} \to 3S + 2{H_2}O\\
S + {O_2} \xrightarrow{t^0} S{O_2}\\
2S{O_2} + {O_2} \xrightarrow{t^0,V_2O_5} 2S{O_3}\\
S{O_3} + {H_2}O \to {H_2}S{O_4}\\
2NaCl + {H_2}S{O_4} \to N{a_2}S{O_4} + 2HCl\\
Mn{O_2} + 4HCl \to MnC{l_2} + C{l_2} + 2{H_2}O\\
3C{l_2} + 6KOH \to KCl{O_3} + 5KCl + 3{H_2}O\\
2KCl{O_3} \xrightarrow{t^0} 2KCl + 3{O_2}\\
2{H_2}S + {O_2} \to 2{H_2}O + 2S\\
S + {H_2} \to {H_2}S\\
2{H_2}S + 3{O_2} \xrightarrow{t^0} 2{H_2}O + S{O_2}\\
S{O_2} + 2NaOH \to N{a_2}S{O_3} + {H_2}O\\
N{a_2}S{O_3} + {H_2}S{O_4} \to N{a_2}S{O_4} + S{O_2} + {H_2}O\\
N{a_2}S{O_4} + BaC{l_2} \to BaS{O_4} + 2NaCl\\
2NaCl + 2{H_2}O \xrightarrow{\text{ điện phân dung dịch có màng ngăn }} 2NaOH + C{l_2} + {H_2}\\
d)\\
FeS + 2HCl \to FeC{l_2} + {H_2}S\\
2{H_2}S + 3{O_2} \xrightarrow{t^0} 2S{O_2} + 2{H_2}O\\
S{O_2} + NaOH \to NaHS{O_3}\\
NaHS{O_3} + NaOH \to N{a_2}S{O_3} + {H_2}O\\
N{a_2}S{O_3} + 2HCl \to 2NaCl + S{O_2} + {H_2}O\\
S{O_2} + B{r_2} + 2{H_2}O \to 2HBr + {H_2}S{O_4}\\
2KOH + {H_2}S{O_4} \to {K_2}S{O_4} + 2{H_2}O\\
{K_2}S{O_4} + BaC{l_2} \to BaS{O_4} + 2KCl\\
2KCl + 2{H_2}O \xrightarrow{\text{ điện phân dung dịch có màng ngăn }} 2KOH + C{l_2} + {H_2}\\
6KOH + 3C{l_2} \to 5KCl + KCl{O_3} + 3{H_2}O\\
2KCl{O_3} \xrightarrow{t^0} 2KCl + 3{O_2}\\
2{H_2}S + {O_2} \xrightarrow{t^0} 2{H_2}O + 2S\\
Zn + S \to ZnS\\
2ZnS + 3{O_2} \xrightarrow{t^0} 2ZnO + 2S{O_2}\\
2S{O_2} + {O_2} \xrightarrow{t^0,V_2O_5} 2S{O_3}\\
S{O_3} + Ba{(OH)_2} \to BaS{O_4} + {H_2}O
\end{array}\)