Giúp mình với mình cần gấp lắm rồi

1)

Các phản ứng xảy ra:

a)

\(Ca{C_2} + 2{H_2}O\xrightarrow{{}}Ca{(OH)_2} + {C_2}{H_2}\)

\({C_2}{H_2} + 2{\text{A}}gN{O_3} + 2N{H_3}\xrightarrow{{}}A{g_2}{C_2} + 2N{H_4}N{O_3}\)

\({C_2}{H_2} + {H_2}\xrightarrow{{P{\text{d}}/PbC{O_3}}}{C_2}{H_4}\)

\({C_2}{H_4} + C{l_2}\xrightarrow{{}}{C_2}{H_4}C{l_2}\)

b)

\(2C{H_4}\xrightarrow{{{{1500}^o}C,l\ln }}{C_2}{H_2} + 3{H_2}\)

\({C_2}{H_2} + 2{\text{A}}gN{O_3} + 2N{H_3}\xrightarrow{{}}A{g_2}{C_2} + 2N{H_4}N{O_3}\)\

\({C_2}{H_2} + 2{H_2}\xrightarrow{{Ni,{t^o}}}{C_2}{H_6}\)

\({C_2}{H_6} + C{l_2}\xrightarrow{{as}}{C_2}{H_5}Cl + HCl\)

2)

a)

Gọi công thức của ankan là \(C_nH_{2n+2}\)

\({C_n}{H_{2n + 2}} + (1,5n + 0,5){O_2}\xrightarrow{{{t^o}}}nC{O_2} + (n + 1){H_2}O\)

Ta có:

\({n_{C{O_2}}} = \frac{{8,96}}{{22,4}} = 0,4{\text{ mol < }}{{\text{n}}_{{H_2}O}} = \frac{9}{{18}} = 0,5{\text{ mol}}\)

\( \to {n_A} = {n_{{H_2}O}} - {n_{C{O_2}}} = 0,5 - 0,4 = 0,1{\text{ mol}}\)

\( \to n = \frac{{{n_{C{O_2}}}}}{{{n_A}}} = \frac{{0,4}}{{0,1}} = 4\)

Vậy \(A\) là \(C_4H_{10}\)

CTCT: \(CH_3CH_2CH_2CH_3\): butan

\(CH_3CH(CH_3)CH_3\): 2-metyl propan

b)

Gọi công thức của ankan là \(C_nH_{2n+2}\)

\({C_n}{H_{2n + 2}} + (1,5n + 0,5){O_2}\xrightarrow{{{t^o}}}nC{O_2} + (n + 1){H_2}O\)

Ta có:

\({n_{C{O_2}}} = \frac{{5,6}}{{22,4}} = 0,25{\text{ mol < }}{{\text{n}}_{{H_2}O}} = \frac{5,4}{{18}} = 0,3{\text{ mol}}\)

\( \to {n_A} = {n_{{H_2}O}} - {n_{C{O_2}}} = 0,3 - 0,25 = 0,05{\text{ mol}}\)

\( \to n = \frac{{{n_{C{O_2}}}}}{{{n_A}}} = \frac{{0,25}}{{0,05}} = 5\)

Vậy \(A\) là \(C_5H_{12}\)

CTCT:

\(CH_3CH_2CH_2CH_2CH_3\): pentan

\(CH_3CH(CH_3)CH_2CH_3\): 2-metyl butan

\(CH_3C(CH_3)_2CH_3\): 2,2-dimetyl propan