giúp em với ạ

Đáp án:

Giải thích các bước giải:

 `b) 4x.(3x+2)=0`

`=> \(\left[ \begin{array}{l}4x-0\\3x+1=0\end{array} \right.\) 

\(\left[ \begin{array}{l}x=0\\3x=-1\end{array} \right.\) 

\(\left[ \begin{array}{l}x=0\\x=-1:3\end{array} \right.\) 

\(\left[ \begin{array}{l}x=0\\x=\dfrac{-1}{3}\end{array} \right.\) 

Vậy `x\in{0;-1/3}`

`d) (2x+5) . (x+(-1)/2) = 0 `

`\(\left[ \begin{array}{l}2x+5=0\\x+\dfrac{-1}{2}=0\end{array} \right.\) 

\(\left[ \begin{array}{l}2x=-5\\x=\dfrac{1}{2}\end{array} \right.\) 

\(\left[ \begin{array}{l}x=-5:2\\x=\dfrac{1}{2}\end{array} \right.\) 

\(\left[ \begin{array}{l}x=\dfrac{-5}{2}\\x=\dfrac{1}{2}\end{array} \right.\) 

Vậy `x\in{-5/2;1/2}`

`#Zoee`