Tính B: $\frac{-5}{3}$ .$\frac{11}{2}$ . ($\frac{1}{3}$ + 1)

Đáp án:

 $B= \dfrac{-5}{3}.\dfrac{11}{2}.(\dfrac{1}{3}+1)$

$B= (\dfrac{(-5).11}{3.2}).(\dfrac{1}{3}+\dfrac{3}{3})$

$B= \dfrac{-55}{6}.\dfrac{4}{3}$

$B= \dfrac{-55.2^2}{2.3.3}$

$B= \dfrac{-55.2}{9}$

$B= \dfrac{-110}{9}$