tính cho mình ah thanks

Đáp án:

    `xy - 2x + 3y = 11`

`⇒x(y - 2) + 3y - 6 = 11 - 6 = 5`

`⇒x(y - 2) + 3(y - 2) = 5`

`⇒(y - 2).(x + 3) = 5`

`text{Ta có bảng sau :}`

\begin{array}{|c|c|c|}\hline \text{x+3}&\text{1}&\text{5}&\text{-1}&\text{-5}\\\hline \text{y-2}&\text{5}&\text{1}&\text{-5}&\text{-1}\\\hline \text{x}&\text{-2}&\text{2}&\text{-4}&\text{-8}\\\hline \text{y}&\text{7}&\text{3}&\text{-3}&\text{-6}\\\hline\end{array}

`text{Vậy (x;y)=(-2;7)=(2;3)=(-4;-3)=(-8;-6)}`