giải phương trình sau x-1/x+2-x/x-2=7x-6/4-x²

$\text{$\dfrac{x - 1}{x + 2}$ - $\dfrac{x}{x - 2}$ = $\dfrac{7x - 6}{4 - x²}$ Đkxđ: x $\neq$ ±2}$

$\text{⇔ $\dfrac{x - 1}{x + 2}$ - $\dfrac{x}{x - 2}$ = -$\dfrac{7x - 6}{x² - 4}$ }$

$\text{⇔ $\dfrac{(x - 1)(x - 2) - x(x + 2)}{(x - 2)(x + 2)}$ = $\dfrac{-7x + 6}{(x - 2)(x + 2)}$ }$

$\text{⇒ x² - 2x - x + 2 - x² - 2x = -7x + 6}$

$\text{⇔ -5x + 2 = -7x + 6}$

$\text{⇔ -5x + 7x = 6 - 2}$

$\text{⇔ 2x = 4}$

$\text{⇔ x = 2 (Không t/m)}$

$\text{⇒ x ∈ ∅}$

$\text{Vậy phương trình vô nghiệm}$

$\textit{Ha1zzz}$