Viết pt phản ứng cho dãy chuyển hoá sau: C6H6 <- C2H2 -> C2H4 -> C2H4Br2 -> C2H2 -> C2H6 -> C2H5Cl -> C2H5OH -> C4H6 -> cao su buna

Đáp án:

Giải thích các bước giải:

CH≡CH$\xrightarrow[600^0 C]{bột C}$ $C_6$$H_6$

CH≡CH +$H_2$ $\xrightarrow[Pd/PbCO3]{t^0}$ $CH_2$=$CH_2$

$CH_2$=$CH_2$ +$Br_2$→$CH_2$Br-$CH_2$Br

$CH_2$Br-$CH_2$Br +2KOH→CH≡CH+2$H_2$O+2KBr

CH≡CH +2$H_2$$\xrightarrow[Ni]{t^0}$ $CH_3$-$CH_3$

C$H_3$C$H_3$ + C$l_2$ $\xrightarrow[as]{t^0}$ $CH_3$$CH_2$Cl

C$H_3$C$H_2$Cl+ $H_2$O→C$H_3$C$H_2$OH

2C$H_3$C$H_2$OH $\xrightarrow[Al2O3]{t^0}$ C$H_2$=CH-CH-C$H-2$ +2$H_2$O

nC$H_2$=CH-CH-C$H-2$ $\xrightarrow{xt,p,t^0}$ (C$H_2$=CH-CH-C$H_2$)n