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Answer
$A = 81 . \left(\dfrac{12 - \dfrac{12}{7} - \dfrac{12}{289} - \dfrac{12}{85}}{4 - \dfrac{4}{7} - \dfrac{4}{289} - \dfrac{4}{85}} : \dfrac{5 + \dfrac{5}{13} + \dfrac{5}{169} + \dfrac{5}{99}}{6 + \dfrac{6}{13} + \dfrac{6}{169} + \dfrac{6}{91}}\right) . \dfrac{158158158}{711711711}$
$A = 81 . \left(\dfrac{12 . \left(1 - \dfrac{1}{7} - \dfrac{1}{289} - \dfrac{1}{85}\right)}{4 . \left(1 - \dfrac{1}{7} - \dfrac{1}{289} - \dfrac{1}{85}\right)} : \dfrac{5 . \left(1 + \dfrac{1}{13} + \dfrac{1}{169} + \dfrac{1}{99}\right)}{6 . \left(1 + \dfrac{1}{13} + \dfrac{1}{169} + \dfrac{1}{99}\right)}\right) . \dfrac{2}{9}$
$A = 81 . \left(\dfrac{12}{4} : \dfrac{5}{6}\right) . \dfrac{2}{9}$
$A = 81 . \dfrac{18}{5} . \dfrac{2}{9}$
$A = \dfrac{1458}{5} . \dfrac{2}{9}$
$A = \dfrac{324}{5}$
Vậy $A = \dfrac{324}{5}$
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Đáp án:
$81\cdot \left(\:\dfrac{12-\dfrac{12}{7}-\dfrac{12}{289}-\dfrac{12}{85}}{4-\dfrac{4}{7}-\dfrac{4}{289}-\dfrac{4}{85}}\::\:\dfrac{5+\dfrac{5}{13}+\dfrac{5}{169}+\dfrac{5}{99}}{6+\dfrac{6}{13}+\dfrac{6}{169}+\dfrac{6}{91}}\:\right)\:\cdot \dfrac{158158158}{711711711}$ $=\dfrac{20753172}{320005}$
Giải thích các bước giải:
$81\cdot \left(\:\dfrac{12-\dfrac{12}{7}-\dfrac{12}{289}-\dfrac{12}{85}}{4-\dfrac{4}{7}-\dfrac{4}{289}-\dfrac{4}{85}}\::\:\dfrac{5+\dfrac{5}{13}+\dfrac{5}{169}+\dfrac{5}{99}}{6+\dfrac{6}{13}+\dfrac{6}{169}+\dfrac{6}{91}}\:\right)\:\cdot \dfrac{158158158}{711711711}$
$=\:81\cdot \left(\:\dfrac{\frac{102192}{10115}}{\dfrac{34064}{10115}}\::\:\dfrac{\frac{91430}{16731}}{\dfrac{7764}{1183}}\:\right)\:\cdot \dfrac{2}{9}$
$=\:81\cdot \left(\:3\::\:\dfrac{320005}{384318}\:\right)\:\cdot \dfrac{2}{9}$
$=\:81\cdot \dfrac{1152954}{320005}\:\cdot \dfrac{2}{9}$
$=\dfrac{81}{1}\cdot \dfrac{1152954}{320005}\cdot \dfrac{2}{9}$
$=\dfrac{81\cdot \:1152954\cdot \:2}{1\cdot \:320005\cdot \:9}$
$=\dfrac{9\cdot \:9\cdot \:1152954\cdot \:2}{2880045}$
$=\dfrac{9\cdot \:9\cdot \:1152954\cdot \:2}{9\cdot \:320005}$
$=\dfrac{9\cdot \:1152954\cdot \:2}{320005}$
$=\dfrac{20753172}{320005}$
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