Bài toán: Chứng minh rằng:
$\text{S =}$ $\frac{1}{2^{2}}$ $\text{-}$ $\frac{1}{2^{4}}$ $\text{+}$ $\frac{1}{2^{6}}$ $\text{-}$ $\text{...}$ $\text{+}$ $\frac{1}{2^{4n - 2}}$ $\text{-}$ $\frac{1}{2^{4n}}$ $\text{+}$ $\text{...}$ $\text{+}$ $\frac{1}{2^{2002}}$ $\text{-}$ $\frac{1}{2^{2004}}$ $\text{<}$ $\text{0,2}$
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thanks ạ <3
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ko có j :>