IV. CÂN BẰNG PHƯƠNG TRÌNH 52. Al + O2 ---> Al2O3 53. Fe + O2 ---> Fe3O4 54. Al(OH)3 ---> Al2O3 + H2O 55. Fe(OH)3 ---> Fe2O3 + H2O 56. Li + O2 ---> Li2O 57. H3PO4 + NaOH --> Na3PO4 + H2O 58. H2SO4 + KOH --> K2SO4 + H2O 59. Fe2(SO4)3 + NaOH --> Na2SO4 + Fe(OH)3 60. H2SO4 + NaOH --> Na2SO4 + H2O 61. Cu + AgNO3 ---> Cu(NO3)2 + Ag 62. Zn + AgNO3 ---> Zn(NO3)2 + Ag 63. Fe + AgNO3 ---> Fe(NO3)2 + Ag 64. Al + AgNO3 ---> Al(NO3)3 + Ag 65. Fe + Cl2 ---> FeCl3 66. Al + S ---> Al2S3 67. Fe2(SO4)3 + KOH ---> K2SO4 + Fe(OH)3 68. Fe(OH)3 ---> Fe2O3 + H2O

Đáp án:

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Giải thích các bước giải:

`52.` `4Al` + $3O_{2}$ $→^{to}$ $2Al_{2}$$O_{3}$

`53.` `3Fe` + $2O_{2}$ $→^{to}$ $Fe_{3}$$O_{4}$

`54.` $2Al(OH)_{3}$ $→^{to}$ $Al_{2}$$O_{3}$ + $3H_{2}$`O`

`55.` $2Fe(OH)_{3}$ $→^{to}$ $Fe_{2}$$O_{3}$ + $3H_{2}$`O`

`56.` `4Li` + $O_{2}$ $→^{to}$ $2Li_{2}$`O`

`57.` $H_{3}$$PO_{4}$ + `3NaOH` `→` $Na_{3}$$PO_{4}$ + $3H_{2}$`O`

`58.` $H_{2}$$SO_{4}$ +`2KOH` `→` $K_{2}$$SO_{4}$ + $2H_{2}$`O`

`59.` $Fe_{2}$$(SO4)_{3}$ + `6NaOH` `→` $3Na_{2}$$SO_{4}$ + $2Fe(OH)_{3}$`↓`

`60.` $H_{2}$$SO_{4}$ + `2NaOH` `→` $Na_{2}$$SO_{4}$ + $2H_{2}$`O`

`61.` `Cu` + $2AgNO_{3}$ `→` $Cu(NO3)_{2}$ + `2Ag`

`62.` `Zn` + $2AgNO_{3}$ `→` $Zn(NO3)_{2}$ + `2Ag`

`63.` `Fe` + $2AgNO_{3}$ `→` $Fe(NO3)_{2}$ + `2Ag`

`64.` `Al` + $3AgNO_{3}$ `→` $Al(NO3)_{3}$ + `3Ag`

`65.` `2Fe` + $3Cl_{2}$ $→^{to}$ $2FeCl_{3}$

`66.` `2Al` + `3S` $→^{to}$ $Al_{2}$$S_{3}$

`67.` $Fe_{2}$$(SO4)_{3}$ + `6KOH` `→` $3K_{2}$$SO_{4}$ + $2Fe(OH)_{3}$

`68.` $2Fe(OH)_{3}$ $→^{to}$ $Fe_{2}$$O_{3}$ + $3H_{2}$`O`