giải các phương trình sau (3/4x - 2)(5/3x + 1)=0 (5x + 3)(3x + 11/4 - x-7/12)=0

Đáp án:

Giải thích các bước giải:

 `(3/4 x-2 )(5/3 x+1)=0`

`=>`\(\left[ \begin{array}{l}\dfrac{3}{4}x -2=0\\\dfrac{5}{3}x+1=0\end{array} \right.\) $\\$`=>`\(\left[ \begin{array}{l}x=\dfrac{8}{3}\\x=\dfrac{-3}{5}\end{array} \right.\) $\\$Vậy `S={-3/5 ;8/3}`

`(5x+3)(3x+[11]/4 -x-7/[12] )=0`

`=>(5x+3)(2x+[13]/6 )=0`

`=>`\(\left[ \begin{array}{l}5x+3=0\\2x+\dfrac{13}{6}=0\end{array} \right.\) $\\$`=>`\(\left[ \begin{array}{l}x=\dfrac{-3}{5}\\x=\dfrac{-13}{12}\end{array} \right.\) $\\$Vậy `S={-3/5 ; -13/12 }`