tìm x để 4x-1 chia hết cho 2x-3

$4x-1$ ⋮ $2x-3$

⇔$4x-1 - 2$($2x-3$) ⋮ $2x-3$

⇔$4x - 1 - 4x + 6$ ⋮ $2x-3$

⇔        $5$            ⋮ $2x-3$

⇒$2x-3$ ∈ Ư($5$)={$±1;±5$}

⇔$2x$ ∈ {$-2;2;4;8$}

⇔$x$ ∈ {$-1;1;2;4$}

 Vậy $x$ ∈ {$-1;1;2;4$}